
Оле на День рожденье подарили коробку конф, 1/5 съела сама Оля, 1/3 съел Коля, утроенную разность
съеденных Колей и Олей конфет взял Вася, после чего в коробке осталось 1 конфета. Сколько конфет съел Коля? А) 3 Б) 5 В) 6 Г) 8 помогите пожалуйста очень срочно

Ответы на вопрос

2/15*3=6/15 взял вася
1/3+1/5+6/15=14/15 конфет съели трое
15/15-14/15=1/15 остаток равен одной конфете
значит в коробке 15 конфет
1/3*15=5 конфет съел коля



Problem Analysis
In this problem, we are given that Olga received a box of candies for her birthday. Olga ate 1/5 of the candies, while Kolya ate 1/3 of the candies. Vasya then took the triple difference between the number of candies eaten by Kolya and Olga, and after that, there was only 1 candy left in the box. We need to determine how many candies Kolya ate.Solution
Let's assume that the total number of candies in the box was x.According to the problem, Olga ate 1/5 of the candies, which is (1/5)x.
Kolya ate 1/3 of the candies, which is (1/3)x.
The triple difference between the number of candies eaten by Kolya and Olga is 3 * ((1/3)x - (1/5)x).
After Vasya took the triple difference, there was only 1 candy left in the box. So, we can set up the equation:
x - (1/5)x - (1/3)x - 3 * ((1/3)x - (1/5)x) = 1
Simplifying the equation:
x - (1/5)x - (1/3)x - 3 * ((1/3)x - (1/5)x) = 1 => x - (1/5)x - (1/3)x - 3 * (5/15)x + 3 * (3/15)x = 1 => x - (1/5)x - (1/3)x - (15/15)x + (9/15)x = 1 => x - (1/5)x - (1/3)x - (15/15)x + (9/15)x = 1 => x - (3/15)x - (5/15)x - (15/15)x + (9/15)x = 1 => x - (3 + 5 + 15 - 9)/15x = 1 => x - 14/15x = 1 => (15/15)x - 14/15x = 1 => (1/15)x = 1 => x = 15
Therefore, the total number of candies in the box was 15.
To find out how many candies Kolya ate, we can substitute the value of x into the expression for Kolya's share:
(1/3)x = (1/3) * 15 = 5
So, Kolya ate 5 candies.
Answer
Kolya ate 5 candies (option B).Note: The search result snippet provided does not directly answer the question. However, the solution provided above is derived from the given problem statement and does not require external sources.


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