Question

Из точки А и точки В на встречу друг другу одновременно выехали 2 велосипедиста.Расстояние между точками равно 200 км.Они встретились черёд 5 часов.с какой скоростью двигался первый велосипедист,если скорость второго была равна 18 км/час

Answer 1

1)18•5=90 (км ) второй за 5 часов
2)200-90=110(км) первый за 5 часов
3)110:5=22 (км/ч) скорость первого

Answer 2

Problem Analysis

Two cyclists start simultaneously from points A and B and meet after 5 hours. The distance between points A and B is 200 km. The speed of the second cyclist is given as 18 km/h. We need to find the speed of the first cyclist.

Solution

Let's assume the speed of the first cyclist is x km/h.

We can use the formula: distance = speed × time to calculate the distance traveled by each cyclist.

The first cyclist travels for 5 hours at a speed of x km/h, so the distance traveled by the first cyclist is 5x km.

The second cyclist travels for 5 hours at a speed of 18 km/h, so the distance traveled by the second cyclist is 5 × 18 = 90 km.

Since the total distance between points A and B is 200 km, we can set up the equation: distance traveled by the first cyclist + distance traveled by the second cyclist = total distance.

This can be written as: 5x + 90 = 200.

Now, we can solve this equation to find the value of x.

Calculation

Let's solve the equation 5x + 90 = 200 to find the value of x.

Subtracting 90 from both sides of the equation, we get: 5x = 110.

Dividing both sides of the equation by 5, we get: x = 22.

Answer

Therefore, the speed of the first cyclist is 22 km/h.

Conclusion

The first cyclist was traveling at a speed of 22 km/h, while the second cyclist was traveling at a speed of 18 km/h. They met after 5 hours of cycling.