Question

Корове и 6 овцам дали за день 30 кг свёклы. Корове дали 12 кг,а остальное - овцам,поровну каждой.Во сколько раз меньше свёклы съела за день одна овца,чем корова?

Answer 1

1) 30-12=18(кг) свеклы дали 6 овцам                                                                  2) 18:6=3(кг) свеклы на одну овцу                                                                     3) 12:3=4(в 4 раза меньше съела овца)                                                                 Ответ: Овца съедает за день в 4 раза меньше свеклы,чем корова.

Answer 2

Problem Analysis

We are given that a cow and 6 sheep were given a total of 30 kg of beets in a day. The cow received 12 kg, and the rest was divided equally among the sheep. We need to find out how many times less beets one sheep ate compared to the cow.

Solution

To solve this problem, we need to calculate the amount of beets each sheep received and then compare it to the amount the cow received.

Let's start by calculating the amount of beets each sheep received. Since the remaining beets were divided equally among the 6 sheep, we can divide the remaining beets by the number of sheep:

Remaining beets = Total beets - Beets given to the cow Remaining beets = 30 kg - 12 kg = 18 kg

Amount of beets each sheep received = Remaining beets / Number of sheep Amount of beets each sheep received = 18 kg / 6 = 3 kg

Now, let's compare the amount of beets one sheep ate to the amount the cow ate:

Ratio of beets eaten by one sheep to the cow = Amount of beets one sheep ate / Amount of beets the cow ate Ratio of beets eaten by one sheep to the cow = 3 kg / 12 kg = 1/4

Therefore, one sheep ate 1/4 times less beets than the cow.

Answer

One sheep ate 1/4 times less beets than the cow.