Question

Из точки А и точки В на встречу друг другу одновремено выехали 2 велосипедиста. Растение между точками равно 200м. Они встретились через 5часов. С какой скоростью двигается первый велосипедист ,если скорость второго была равна 18км/ч?

Answer 1

Велосипедисты выехали навстречу одновременно, значит мы можем найти скорость их сближения 200:5=40 км/ч.
скорость сближения равна сумме скоростей сближающихся объектов, значит легко найдем скорость первого велосипедиста 40-18=22 км/ч
Ответ: первый велосипедист двигается со скоростью 22 км/ч

Answer 2

Problem Analysis

We have two cyclists who start simultaneously from point A and point B and meet after 5 hours. The distance between the two points is 200 meters. We are given the speed of the second cyclist, which is 18 km/h. We need to find the speed of the first cyclist.

Solution

To solve this problem, we can use the formula: speed = distance / time.

Let's calculate the speed of the first cyclist.

Calculation

The distance between the two cyclists is 200 meters.

The time taken to meet is 5 hours.

Using the formula speed = distance / time, we can calculate the speed of the first cyclist:

speed = 200 meters / 5 hours.

Converting the speed to km/h:

speed = (200 meters / 5 hours) * (1 km / 1000 meters) * (1 hour / 1 hour).

Simplifying the expression:

speed = 0.04 km/h.

Therefore, the speed of the first cyclist is 0.04 km/h.

Answer

The first cyclist is moving at a speed of 0.04 km/h.

Note: The speed of the first cyclist seems unusually low. Please double-check the given information to ensure its accuracy.