Question

Ахиллес бежит за черепахой со скоростью 3м/с.Между ними 100 м . На какой по счёту секунде Ахиллес догонит черепху , которая ползёт в 100 раз медленнее, чем бежит Ахиллес?

Answer 1

Решение:

1)3:100=0,3м/с - скор. черепахи

2)100:(3-0,03)=через 33,7с

 

Answer 2

Problem Analysis

We are given that Achilles is running at a speed of 3 m/s and the distance between Achilles and the tortoise is 100 m. The tortoise is crawling at a speed that is 100 times slower than Achilles. We need to determine at which second Achilles will catch up to the tortoise.

Solution

To solve this problem, we can calculate the time it takes for Achilles to cover the distance between them. Since the tortoise is moving at 100 times slower than Achilles, we can calculate the time it takes for the tortoise to cover the same distance. The difference in time will give us the answer.

Let's calculate the time it takes for Achilles to cover the distance of 100 m:

Distance = Speed × Time

100 m = 3 m/s × Time

Time = 100 m / 3 m/s

Now, let's calculate the time it takes for the tortoise to cover the same distance, but at a speed that is 100 times slower than Achilles:

Time for the tortoise = Time for Achilles × 100

Time for the tortoise = (100 m / 3 m/s) × 100

Finally, we subtract the time it takes for the tortoise from the time it takes for Achilles to find the answer:

Time difference = Time for Achilles - Time for the tortoise

Let's calculate the values:

Time for Achilles = 100 m / 3 m/s = 33.33 s

Time for the tortoise = (100 m / 3 m/s) × 100 = 3333.33 s

Time difference = 33.33 s - 3333.33 s = -3300 s

Since the time difference is negative, it means that Achilles will never catch up to the tortoise. This is because the tortoise is always ahead of Achilles, no matter how small the distance becomes.

Therefore, Achilles will never catch up to the tortoise.

Conclusion

Achilles will never catch up to the tortoise because the tortoise is always ahead, no matter how small the distance becomes.