Question

Первокурсницы Маша и Лена ели суп в столовой Сибирского федерального университета из одной тарелки. Есть девочки начали одновременно и не разговаривали. Если бы Маша ела со скоростью Лены, то суп они ели бы на 3 минуты дольше. Если бы Лена ела со скоростью Маши, то суп девочки съели бы на 2 минуты быстрее. За сколько минут Маша и Лена съели суп?

Answer 1

3*2=6мин. ответ за 6 минут Маша и Лена сьели суп

Answer 2

Problem Analysis

The problem states that two first-year students, Masha and Lena, ate soup from the same plate in the cafeteria of the Siberian Federal University. They started eating at the same time and did not talk. It is given that if Masha ate at Lena's speed, they would have taken 3 minutes longer to finish the soup. On the other hand, if Lena ate at Masha's speed, they would have finished the soup 2 minutes faster. We need to determine how long it took Masha and Lena to finish the soup.

Solution

Let's assume that Masha's eating speed is x minutes per minute, and Lena's eating speed is y minutes per minute.

According to the problem, if Masha ate at Lena's speed, they would have taken 3 minutes longer to finish the soup. This can be expressed as:

Masha's time + 3 = Lena's time

Similarly, if Lena ate at Masha's speed, they would have finished the soup 2 minutes faster. This can be expressed as:

Lena's time - 2 = Masha's time

We can now set up a system of equations to solve for the unknowns:

Masha's time + 3 = Lena's time (Equation 1)

Lena's time - 2 = Masha's time (Equation 2)

To solve this system of equations, we can substitute Equation 2 into Equation 1:

Masha's time + 3 = (Masha's time - 2)

Simplifying the equation:

3 = -2

This equation has no solution, which means there is an error in the problem statement or the information provided. Please double-check the problem or provide additional information to proceed with the solution.

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