Question

Из города С и А расстояние между которыми равно 320 км, выехали одновременно навстречу друг другу два мотоциклиста, скорость одного из них была на 5 км/ч больше скорости другог. Через 2 часа мотоциклисты оказались на расстоянии 20 км друг от друга. С какой скоростью ехал каждый мотоциклист?

Answer 1

320-20=300 км - проехали мотоциклисты за 2 часа
х - скорость 1 мотоциклиста
х+5 - скорость 2 мотоциклиста
(х+х+5)*2=300
4х+10=300
4х=290
х=290/4
х=72,5 км/ч - скорость 1 мотоциклиста
72,5+5=77,5 км/ч - скорость 2 мотоциклиста

Answer 2

Problem Analysis

We have two motorcyclists who start from cities C and A, which are 320 km apart. They are traveling towards each other. One motorcyclist is traveling 5 km/h faster than the other. After 2 hours, they are 20 km apart. We need to find the speed of each motorcyclist.

Solution

Let's assume the speed of the slower motorcyclist is x km/h. Then the speed of the faster motorcyclist will be x + 5 km/h.

We can use the formula distance = speed × time to solve this problem.

After 2 hours, the slower motorcyclist will have traveled a distance of 2x km, and the faster motorcyclist will have traveled a distance of 2(x + 5) km.

The sum of the distances traveled by both motorcyclists should be equal to the total distance between the cities, which is 320