Question

Два брата одновременно вышли из дома и направились в школу.Старший брат шел со скоростью 80м/мин .Младший брат шел школу со скоростью на 30м\мин меньшей,чем скорость старшего брата ,поэтому он пришел в школу на 6 мин позже.за сколько мин дошел до школы старший брат.ПЛИИИИЗЗЗЗ ДАЮ 10 БАЛЛОВ

Answer 1

1 способ
1) 80-30=50 м/мин скорость младшего брата
2) 50*6=300 м расстояние между младшем братом и старшим
3) 300:30=10 минут время за которое дошел до школы младший брат

2 способ
Пусть х минут, время за которое старший брат доходит до школы. Тогда расстояние до школы 80х метров. Время за которое младший брат доходит до школы (х+6) минут.  Скорость младшего брата (80-30) м/ мин, а расстояние (х+6)(80-30) метров. Составим и решим уравнение:
80х=(х+6)(80-30)
80х=(х+6)*50
80х=50х+300
80х-50х=300
30х=300
х=300:30
х=10 минут - старший брат дошел до школы

Ответ за 10 минут

Answer 2

Problem Analysis

We are given that two brothers left home simultaneously and headed to school. The older brother walked at a speed of 80 m/min, while the younger brother walked at a speed 30 m/min slower than the older brother. The younger brother arrived at school 6 minutes later than the older brother. We need to determine how many minutes it took the older brother to reach the school.

Solution

Let's assume that the time taken by the older brother to reach the school is t minutes. Since the younger brother walks at a speed 30 m/min slower than the older brother, his speed is 80 - 30 = 50 m/min.

We can use the formula distance = speed × time to calculate the distance covered by each brother.

For the older brother: - Distance = Speed × Time - Distance = 80 m/min × t min - Distance = 80t meters

For the younger brother: - Distance = Speed × Time - Distance = 50 m/min × (t + 6) min - Distance = 50(t + 6) meters

Since both brothers are traveling the same distance, we can equate the distances and solve for t.

80t = 50(t + 6)

Simplifying the equation:

80t = 50t + 300

30t = 300

t = 10

Therefore, it took the older brother 10 minutes to reach the school.

Answer

The older brother took 10 minutes to reach the school.

Explanation

The older brother walked at a speed of 80 m/min, while the younger brother walked at a speed 30 m/min slower than the older brother. The younger brother arrived at school 6 minutes later than the older brother. By equating the distances covered by both brothers, we can solve for the time taken by the older brother. It turns out that the older brother took 10 minutes to reach the school