Question

Второе из трех чисел равно 132 и составляет 0,55 их суммы. А первое 0,2 суммы. Найдите первое и третье числа.

Answer 1

Второе число равно 132 и составляет 0,55 от суммы трех чисел.
Значит, сумма трех чисел равна 132/0,55 = 240
А сумма 1 и 3 чисел равна 240 - 132 = 108.
Первое число равно 0,2 от суммы, то есть 0,2*240 = 48.
А третье равно 108 - 48 = 60.

Answer 2

To solve this problem, let's assign variables to the three numbers. Let's call the first number "x", the second number "132", and the third number "y".

According to the problem, the second number is equal to 132 and makes up 0.55 of their sum. The first number is 0.2 of the sum. We can express this information in equations:

Equation 1: 132 = 0.55(x + 132 + y) Equation 2: x = 0.2(x + 132 + y)

Now, let's solve these equations step by step to find the values of x and y.

Step 1: Solve Equation 2 for x: x = 0.2(x + 132 + y) Multiply both sides by 10 to eliminate the decimal: 10x = 2(x + 132 + y) Distribute: 10x = 2x + 264 + 2y Simplify: 10x - 2x = 2y + 264 8x = 2y + 264 Divide both sides by 8: x = (2y + 264) / 8 x = 0.25y + 33

Step 2: Substitute the value of x in Equation 1: 132 = 0.55(x + 132 + y) 132 = 0.55((0.25y + 33) + 132 + y) 132 = 0.55(0.25y + y + 165) 132 = 0.55(1.25y + 165) 132 = 0.6875y + 90.75 132 - 90.75 = 0.6875y 41.25 = 0.6875y Divide both sides by 0.6875: y = 60

Step 3: Substitute the value of y back into Equation 2 to find x: x = 0.25y + 33 x = 0.25(60) + 33 x = 15 + 33 x = 48

Therefore, the first number is 48, the second number is 132, and the third number is 60.