
На одной автостоянке было в 6 раза (раз) меньше машин, чем на другой. Когда со второй стоянки на
первую перевели 72 автомобилей(-я), машин на стоянках стало поровну. Какое количество машин было на каждой стоянке первоначально?

Ответы на вопрос

4х-12=х+12
4х-х=24
3х=24
х=8
8*4=32
Ответ: на одной было 8 машин, а на другой 32 машины.


Problem Analysis
We are given two parking lots, and the number of cars on one lot is 6 times less than the number of cars on the other lot. When 72 cars are moved from the second lot to the first lot, the number of cars becomes equal on both lots. We need to determine the initial number of cars on each parking lot.
Solution
Let's assume the initial number of cars on the first parking lot is x and the initial number of cars on the second parking lot is y.
According to the problem, the number of cars on the first lot is 6 times less than the number of cars on the second lot. This can be expressed as:
x = y - 6y
Simplifying the equation, we get:
x = -5y
When 72 cars are moved from the second lot to the first lot, the number of cars becomes equal on both lots. This can be expressed as:
x + 72 = y - 72
Substituting the value of x from the first equation, we get:
-5y + 72 = y - 72
Simplifying the equation, we get:
6y = 144
Dividing both sides of the equation by 6, we get:
y = 24
Substituting the value of y back into the first equation, we get:
x = -5 * 24 = -120
Since the number of cars cannot be negative, we can conclude that there were initially 120 cars on the first parking lot and 24 cars on the second parking lot.
Answer
The initial number of cars on each parking lot was 120 cars on the first lot and 24 cars on the second lot.


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