
Уравнения: Нужны решения, буду благодарен. I. а) -6,8 - 1/3x = 7,2 б) x * (9,8 + 2x) = 0 в) -3,1 +
1/6x = 3,5 г) (5,6 - 2x) * x = 0 II. а) -2,8 * (3x + 7) - 4,2 = 1,4 б) 2x = x * (x + 1,5) в) - 1,3 * (7 + 4x) - 11 = -4,5 г) (x - 2,3) * x = 4x

Ответы на вопрос





I'll be happy to help you solve these equations! Let's go through each equation step by step and find the solutions.
I. а) -6.8 - 1/3x = 7.2
To solve this equation, we can start by isolating the variable x.
First, let's get rid of the decimal by multiplying the entire equation by 3 to eliminate the fraction:
-20.4 - x = 21.6
Next, we can isolate x by adding 20.4 to both sides of the equation:
- x = 21.6 + 20.4
Simplifying, we have:
- x = 42
Finally, we can multiply both sides of the equation by -1 to solve for x:
x = -42
So the solution to the equation -6.8 - 1/3x = 7.2 is x = -42.
б) x * (9.8 + 2x) = 0
To solve this equation, we can expand the expression on the left side:
9.8x + 2x^2 = 0
Now, we have a quadratic equation. We can rearrange it into standard quadratic form by moving all the terms to one side:
2x^2 + 9.8x = 0
Next, we can factor out the common factor of x:
x(2x + 9.8) = 0
To find the solutions, we can set each factor equal to zero and solve for x:
x = 0 or 2x + 9.8 = 0
For the second equation, we can subtract 9.8 from both sides:
2x = -9.8
Dividing both sides by 2, we get:
x = -4.9
So the solutions to the equation x * (9.8 + 2x) = 0 are x = 0 and x = -4.9.
в) -3.1 + 1/6x = 3.5
To solve this equation, we can start by isolating the variable x.
First, let's get rid of the fraction by multiplying the entire equation by 6:
-18.6 + x = 21
Next, we can isolate x by adding 18.6 to both sides of the equation:
x = 21 + 18.6
Simplifying, we have:
x = 39.6
So the solution to the equation -3.1 + 1/6x = 3.5 is x = 39.6.
г) (5.6 - 2x) * x = 0
To solve this equation, we can apply the zero product property, which states that if a product of two factors equals zero, then at least one of the factors must be zero.
Setting each factor equal to zero, we have:
5.6 - 2x = 0 or x = 0
For the first equation, we can subtract 5.6 from both sides:
-2x = -5.6
Dividing both sides by -2, we get:
x = 2.8
So the solutions to the equation (5.6 - 2x) * x = 0 are x = 2.8 and x = 0.
II. а) -2.8 * (3x + 7) - 4.2 = 1.4
To solve this equation, we can start by simplifying the expression on the left side:
-8.4x - 19.6 - 4.2 = 1.4
Next, we can combine like terms:
-8.4x - 23.8 = 1.4
To isolate x, we can add 23.8 to both sides:
-8.4x = 25.2
Dividing both sides by -8.4, we get:
x = -3
So the solution to the equation -2.8 * (3x + 7) - 4.2 = 1.4 is x = -3.
б) 2x = x * (x + 1.5)
To solve this equation, we can start by distributing x to the terms inside the parentheses:
2x = x^2 + 1.5x
Next, we can rearrange the equation into standard quadratic form by moving all the terms to one side:
x^2 + 1.5x - 2x = 0
Simplifying, we have:
x^2 - 0.5x = 0
To factor out the common factor of x, we have:
x(x - 0.5) = 0
Setting each factor equal to zero, we have:
x = 0 or x - 0.5 = 0
For the second equation, we can add 0.5 to both sides:
x = 0.5
So the solutions to the equation 2x = x * (x + 1.5) are x = 0 and x = 0.5.
в) -1.3 * (7 + 4x) - 11 = -4.5
To solve this equation, we can start by simplifying the expression on the left side:
-9.1 - 5.2x - 11 = -4.5
Next, we can combine like terms:
-5.2x - 20.1 = -4.5
To isolate x, we can add 20.1 to both sides:
-5.2x = 15.6
Dividing both sides by -5.2, we get:
x = -3
So the solution to the equation -1.3 * (7 + 4x) - 11 = -4.5 is x = -3.
г) (x - 2.3) * x = 4x
To solve this equation, we can start by simplifying the expression on the left side:
x^2 - 2.3x = 4x
Next, we can rearrange the equation into standard quadratic form by moving all the terms to one side:
x^2 - 6.3x = 0
To factor out the common factor of x, we have:
x(x - 6.3) = 0
Setting each factor equal to zero, we have:
x = 0 or x - 6.3 = 0
For the second equation, we can add 6.3 to both sides:
x = 6.3
So the solutions to the equation (x - 2.3) * x = 4x are x = 0 and x = 6.3.
I hope this helps! Let me know if you have any further questions.


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