Question

Стеклянная бутылка с водой весит 550 грамм, когда из бутылки вылили 1/2 всей воды ее масса составляла 300 г Сколько грамм воды было в бутылке сначала? Сколько весит Пустая бутылка?

Answer 1

550 - 300 = 250 г полбутылки воды
250 * 2=500 г воды было сначала.

Answer 2

Calculation of Initial Water Weight in the Bottle

To determine the initial weight of water in the bottle, we can use the information provided. We know that the bottle with water weighs 550 grams, and when half of the water is poured out, the weight of the bottle and remaining water is 300 grams.

Let's assume the initial weight of the empty bottle is x grams. Since the weight of the bottle with water is 550 grams, we can subtract the weight of the empty bottle to find the weight of the water:

550 grams (total weight) - x grams (empty bottle weight) = weight of water

Now, when half of the water is poured out, the weight of the bottle and remaining water is 300 grams. We can set up the following equation:

(x grams + weight of remaining water) = 300 grams

Since we poured out half of the water, the weight of the remaining water is half of the initial weight of the water. Let's denote the initial weight of the water as y grams:

(x grams + y grams/2) = 300 grams

Now we have two equations:

1. 550 grams - x grams = y grams 2. x grams + y grams/2 = 300 grams

We can solve these equations to find the values of x and y.

Solving the Equations

To solve the equations, we can use substitution or elimination. Let's use substitution:

From equation 1, we can express y in terms of x:

y grams = 550 grams - x grams

Substituting this value of y into equation 2:

x grams + (550 grams - x grams)/2 = 300 grams

Simplifying the equation:

2x grams + 550 grams - x grams = 600 grams

x grams + 550 grams = 600 grams

x grams = 600 grams - 550 grams

x grams = 50 grams

Now that we have found the weight of the empty bottle (x grams), we can substitute this value back into equation 1 to find the initial weight of the water (y grams):

y grams = 550 grams - 50 grams

y grams = 500 grams

Answer:

Therefore, the initial weight of the water in the bottle was 500 grams. The weight of the empty bottle is 50 grams.

Please note that the calculations above are based on the information provided and the assumption that the weight of the empty bottle remains constant throughout the process.