Question

В первом баке было в 2 раза больше бензина, чем во втором. из первого бака отлили 7 л бензина, а во второй добавили 3 л. после этого бензина в баках стало поровну. сколько бензина было во втором баке?

Answer 1

X - было во втором баке
2x - было в первом баке
2x-7 - стало в первом баке
x+3 - стало во втором баке
x+3=2x-7
x=7+3
x=10 л - было во втором баке

Answer 2

Пусть было во втором баке x; тогда в первом 2x; тк тз первого бака отлили 7 литров, то 2x-7(стало в первом баке); а во второй добавили 3литра, то x+3 (стало во втором баке) можно составить и решить уравнение:
x+3=2x-7
x-2x=-3-7
-x=-10
x=10 (литров)-было во втором баке

Answer 3

Solution:

To solve this problem, we can use a system of equations. Let's denote the amount of gasoline in the first tank as x and the amount of gasoline in the second tank as y.

Given: - In the first tank, there was twice as much gasoline as in the second tank: x = 2y. - 7 liters of gasoline were poured out of the first tank, and 3 liters were added to the second tank, resulting in an equal amount of gasoline in both tanks: x - 7 = y + 3.

We can solve this system of equations to find the amount of gasoline in the second tank.

First, we'll use the equation x = 2y to express x in terms of y: x = 2y.

Then we'll substitute x in the second equation: 2y - 7 = y + 3.

Solving for y: 2y - y = 3 + 7 y = 10.

So, there were 10 liters of gasoline in the second tank.

Answer:

The amount of gasoline in the second tank was 10 liters.