Question

из двух посёлков расстояние между которыми равно 78км Одновременно навстречу друг другу выехали два автомобиля и встретились через 2/3 ч. Скорость одного автомобиля составляла 80% скорости другого. найдите скорость каждого автомобиля. пожалуйста срочно!

Answer 1

X--скорость первого авто
0,8x--скорость второго авто
78км- расстояние между поселками

(x+0,8x)*2/3=78
1,8x*2/3=78
1,2x=78
x=78:1,2
x=65км/ч скорость первого автомобиля
65*0,8=52км/ч скорость второго автомобиля

Answer 2

Problem Analysis

We are given that two cars start from two villages that are 78 km apart and travel towards each other. They meet after 2/3 hours. The speed of one car is 80% of the speed of the other car. We need to find the speed of each car.

Solution

Let's assume the speed of the slower car is x km/h. Then the speed of the faster car will be 0.8x km/h.

We can use the formula speed = distance / time to find the speed of each car.

The time taken by both cars to meet is given as 2/3 hours.

The distance traveled by the slower car is x * (2/3) km.

The distance traveled by the faster car is 0.8x * (2/3) km.

Since the sum of the distances traveled by both cars is equal to the total distance between the villages (78 km), we can write the equation:

x * (2/3) + 0.8x * (2/3) = 78

Simplifying the equation:

(2/3)(x + 0.8x) = 78

(2/3)(1.8x) = 78

1.2x = 78

x = 78 / 1.2

x = 65

So, the speed of the slower car is 65 km/h and the speed of the faster car is 0.8 * 65 = 52 km/h.

Therefore, the speed of each car is 65 km/h and 52 km/h.

Answer

The speed of the slower car is 65 km/h and the speed of the faster car is 52 km/h.