Question

Используя признаки делимости доказать что каждое из данных чисел составное 1)87,88,1533,1050,8125,1096;2)162,369,8126,1055,9898,2016,87090 заранее мерси

Answer 1

1)87делится на 1 на 3 на 87-значит он составной
88делится на 1, 2,4,8,22,44,88-он составной
1533делится на 1,3,1533-он составной
1050делится на 1,2,3,5,10,50 и т д -он составной
8125/1,5, 25,и т д-он составной
1096/1,2,4,...,1096-он составной

Answer 2

Using Divisibility Tests to Show that Each of the Given Numbers is Composite

1) 87, 88, 1533, 1050, 8125, 1096

To show that a number is composite, we can demonstrate that it has divisors other than 1 and itself. We can use various divisibility tests to check for these divisors.

- 87: 87 is divisible by 3, as the sum of its digits (8 + 7) is 15, which is divisible by 3. Therefore, 87 is composite [[1]]. - 88: 88 is divisible by 2, as it ends in an even number. Therefore, 88 is composite [[2]]. - 1533: 1533 is divisible by 3, as the sum of its digits (1 + 5 + 3 + 3) is 12, which is divisible by 3. Therefore, 1533 is composite [[3]]. - 1050: 1050 is divisible by 2 and 5, as it ends in 0 and the sum of its digits (1 + 0 + 5 + 0) is 6, which is divisible by 3. Therefore, 1050 is composite [[4]]. - 8125: 8125 is divisible by 5, as it ends in 5. Therefore, 8125 is composite [[5]]. - 1096: 1096 is divisible by 2, as it ends in an even number. Therefore, 1096 is composite [[6]].

2) 162, 369, 8126, 1055, 9898, 2016, 87090

- 162: 162 is divisible by 2 and 3, as the sum of its digits (1 + 6 + 2) is 9, which is divisible by 3. Therefore, 162 is composite [[7]]. - 369: 369 is divisible by 3, as the sum of its digits (3 + 6 + 9) is 18, which is divisible by 3. Therefore, 369 is composite [[8]]. - 8126: 8126 is divisible by 2, as it ends in an even number. Therefore, 8126 is composite [[9]]. - 1055: 1055 is divisible by 5, as it ends in 5. Therefore, 1055 is composite [[10]]. - 9898: 9898 is divisible by 2, as it ends in an even number. Therefore, 9898 is composite [[11]]. - 2016: 2016 is divisible by 2, 3, and 6, as the sum of its digits (2 + 0 + 1 + 6) is 9, which is divisible by 3. Therefore, 2016 is composite [[12]]. - 87090: 87090 is divisible by 2, 3, 5, and 6, as the sum of its digits (8 + 7 + 0 + 9 + 0) is 24, which is divisible by 3. Therefore, 87090 is composite [[13]].

By applying the divisibility tests, we have shown that each of the given numbers is composite.