Question

Катер плыл 2 ч со скоростью 27км/ч . На обратный путь он потратил на один час больше . С какой скоростью он шёл обратно?

Answer 1

1) 27*2=54 км прошел за 2 часа
2) 2+1=3 часа на обратный путь
3) 54:3=18 км/ч шел обратно
ответ: со скоростью 18 км/ч он шел обратно.

Answer 2

Calculating the Return Speed of the Boat

To find the speed at which the boat traveled on the return trip, we can use the concept of average speed.

Let's denote the speed of the boat on the forward trip as v1 and the speed on the return trip as v2. The total time for the forward trip is 2 hours and the total time for the return trip is 3 hours.

The average speed formula is given by: Average Speed = Total Distance / Total Time

For the forward trip: Total Distance = v1 * 2 (since time = distance / speed)

For the return trip: Total Distance = v2 * 3

Since the total distance covered in both trips is the same, we can set up the equation: v1 * 2 = v2 * 3

Solving for v2: v2 = (v1 * 2) / 3

Now, we can substitute the given speed of the forward trip (27 km/h) into the equation to find the return speed.

v2 = (27 * 2) / 3 v2 = 54 / 3 v2 = 18 km/h

So, the boat traveled at a speed of 18 km/h on the return trip.

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