Question

Длина прямоугольника 24см.Длина в 4 раза больше ширины.Найти периметр и площадь этого прямоугольника.

Answer 1

1)24:4=6(см) - это ширина прямоугольника.
2)P(периметр)=(a+b)*2=2a+2b
P=(24+4)*2=56(см)
3)S=ab
S=24*4=96(см²)
Ответ:P=56 см;S=96 см²

Answer 2

1)24:4=6(см)-ширина
2)24×6=144(см2)-площадь
3)(24+6)×2=60(см)-периметр

Answer 3

Problem Analysis

We are given that the length of a rectangle is 24 cm and that the length is 4 times the width. We need to find the perimeter and area of this rectangle.

Solution

Let's start by finding the width of the rectangle.

From the given information, we know that the length is 4 times the width. So, we can set up the equation:

length = 4 * width

Substituting the given length value of 24 cm, we can solve for the width:

24 cm = 4 * width

Dividing both sides of the equation by 4, we get:

width = 24 cm / 4 = 6 cm

Now that we have the width, we can calculate the perimeter and area of the rectangle.

Perimeter of the Rectangle

The perimeter of a rectangle is given by the formula:

perimeter = 2 * (length + width)

Substituting the values, we get:

perimeter = 2 * (24 cm + 6 cm) = 2 * 30 cm = 60 cm

Therefore, the perimeter of the rectangle is 60 cm.

Area of the Rectangle

The area of a rectangle is given by the formula:

area = length * width

Substituting the values, we get:

area = 24 cm * 6 cm = 144 cm^2

Therefore, the area of the rectangle is 144 cm^2.

Summary

Given that the length of the rectangle is 24 cm and the length is 4 times the width, we have determined that the width is 6 cm. The perimeter of the rectangle is 60 cm, and the area of the rectangle is 144 cm^2.