Question

На школьных соревнаваниях по бегу на дистансии 100м участвовавали однакламники Куаныш и Витя.Когда Куанышу оставалось пробежать одну четвертую дистансии. то Вите одну пятую дистансииКто из мальчиков оказался ближе к финишу и на сколько метров.

Answer 1

Ближе к дистанции оказался Витя. т.к одна пятая дистанции составляет 20 метров,а одна четвертая 25 метров. Витя был ближе к финишу на 5 метров.

Answer 2

100:4=25 (метров)-пробежал Куаныш.
100:5=20 (метров)- пробежал Витя.
25-20=5 (метров)

Answer 3

School Running Competition

Куаныш and Витя participated in a school running competition on a 100m distance. When Куаныш had one-fourth of the distance left to run, Витя had one-fifth of the distance left. Let's calculate who was closer to the finish line and by how many meters.

To solve this problem, we can calculate the distance each of them had left to run when the other had a certain distance left.

Let's start with Куаныш: - When Куаныш had one-fourth of the distance left, it means he had already run 3/4 of the distance. - So, the distance he had left to run is 1/4 * 100m = 25m.

Now, let's calculate the distance Витя had left: - When Витя had one-fifth of the distance left, it means he had already run 4/5 of the distance. - So, the distance he had left to run is 1/5 * 100m = 20m.

Comparing the distances left: - Куаныш had 25m left to run. - Витя had 20m left to run.

Витя was closer to the finish line by 5 meters.