
С железнодорожной станции в 12 ч вышел скорый поезд со скоростью 70 км / ч . На 3 ч раньше с этой
же станции был отправлен в том же направлении товарный поезд . В 16 ч скорый поезд догнал товарный .найдите скорость товарного поезда .

Ответы на вопрос

16-12=4 часа - время скорого в пути
4+3=7 часов - время товарного в пути
4*70=280км - путь
280/7=40км/ч - скорость товарного



16-12=4 часа до встречи
70*4=280 км путь скорого поезда
4+3=7 часов потратил на это расстояние товарный
280/7=40 км/ч скорость товарного



Problem Analysis
We are given that a fast train left a railway station at 12:00 PM with a speed of 70 km/h. Three hours earlier, a freight train was sent in the same direction from the same station. We need to find the speed of the freight train.Solution
To find the speed of the freight train, we can use the concept of relative speed. The relative speed of the fast train with respect to the freight train is the difference between their speeds. Since the fast train catches up to the freight train at 4:00 PM, we can calculate the time it took for the fast train to catch up to the freight train. Then, we can use the formula:Relative Speed = Distance / Time
Let's calculate the time it took for the fast train to catch up to the freight train.
Calculation
The fast train catches up to the freight train at 4:00 PM, which is 4 hours after it left the station. Therefore, the time it took for the fast train to catch up to the freight train is 4 hours.Now, let's calculate the relative speed of the fast train with respect to the freight train.
Relative Speed = Distance / Time
The distance traveled by the fast train in 4 hours can be calculated using the formula:
Distance = Speed * Time
Substituting the values, we have:
Distance = 70 km/h * 4 h = 280 km
Now, let's calculate the speed of the freight train using the formula:
Relative Speed = Distance / Time
Substituting the values, we have:
Relative Speed = Speed of Fast Train - Speed of Freight Train
280 km / 4 h = 70 km/h - Speed of Freight Train
Simplifying the equation, we have:
Speed of Freight Train = 70 km/h - 280 km / 4 h
Calculating the value, we have:
Speed of Freight Train = 70 km/h - 70 km/h = 0 km/h
Therefore, the speed of the freight train is 0 km/h.
Answer
The speed of the freight train is 0 km/h.

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