Question

Два ученика вышли одновременно из своих домов навстречу друг другу первый ученик шел со скоростью 60 метров в минуту и прошел до встречи 480 метров. скорость 2 ученика на 10 м/мин больше скорости 1. какое растояние до встречи прошел 2 ученик

Answer 1

1) 480:60=8км

2) 60+10-70км/ч

3) 70*8=560км

Ответ:560 км прошел до встречи 2 ученик

Answer 2

Problem Analysis

We are given that two students leave their homes simultaneously and walk towards each other. The first student walks at a speed of 60 meters per minute and covers a distance of 480 meters before they meet. The second student's speed is 10 meters per minute faster than the first student's speed. We need to find the distance covered by the second student before they meet.

Solution

Let's assume the speed of the second student is x meters per minute. Since the second student's speed is 10 meters per minute faster than the first student's speed, we can write the equation:

x = 60 + 10

Simplifying the equation, we find:

x = 70

Now, we can calculate the time it takes for the first student to cover the distance of 480 meters using the formula:

time = distance / speed

For the first student:

time1 = 480 / 60 = 8 minutes

Since both students started at the same time, the total time taken for them to meet is 8 minutes. Now, we can calculate the distance covered by the second student using the formula:

distance = speed * time

For the second student:

distance2 = 70 * 8 = 560 meters

Therefore, the second student covered a distance of 560 meters before they met the first student.

Answer

The second student covered a distance of 560 meters before they met the first student.