Question

В трех кусках 75 метров сатина. Во втором куске в 3 раза больше, чем в первом, а в третьем на 30 метров больше, чем в первом. Сколько метров сатина в первом куске? Решать через x! Пожплуйста​

Answer 1

Ответ:

9м

Пошаговое объяснение:

Пусть х-кол-во метров сатина в первом куске, тогда во втором 3х, а в третьем х+30:

х+3х+х+30=75

5х+30=75

5х=75-30

5х=45

х=45:5

х=9(м)-кол-во сатина в первом куске

Answer 2

Problem Analysis

We are given three pieces of satin fabric, and we need to find the length of satin in the first piece. The second piece has three times the length of the first piece, and the third piece has 30 meters more than the first piece.

Solution

Let's assume the length of satin in the first piece is x meters.

According to the given information: - The second piece has three times the length of the first piece, so the length of satin in the second piece is 3x meters. - The third piece has 30 meters more than the first piece, so the length of satin in the third piece is x + 30 meters.

To find the value of x, we can set up the following equation: x + 3x + (x + 30) = 75

Simplifying the equation: 5x + 30 = 75

Subtracting 30 from both sides: 5x = 45

Dividing both sides by 5: x = 9

Therefore, the length of satin in the first piece is 9 meters.

Answer

The length of satin in the first piece is 9 meters.