Question

Пассажир метро, стоящий на ступеньке экскалатора поднимается вверх за 3 минуты. Если он идет вверх, то поднимается за 2 минуты. С какой скоростью идет пассажир метро, если дли эскалатора 150м

Answer 1

1) 3-2=1 (мин)
2)150/1=150 (м/мин)
Ответ:с 150 мин за метр идет пасажир метро

Answer 2

Problem Analysis

We are given that a passenger in a metro station takes 3 minutes to climb up the escalator when standing on a step. However, if the passenger walks up the escalator, they can climb up in 2 minutes. We need to determine the speed at which the passenger is walking.

Solution

Let's assume the speed of the escalator is v m/min and the speed of the passenger walking is w m/min.

When the passenger is standing on the step, the effective speed at which they are climbing is the sum of their walking speed and the speed of the escalator. Therefore, we can write the equation:

w + v = (distance of escalator) / (time taken when standing)

When the passenger is walking up the escalator, their effective speed is the difference between their walking speed and the speed of the escalator. Therefore, we can write the equation:

w - v = (distance of escalator) / (time taken when walking)

We are given that the time taken when standing is 3 minutes and the time taken when walking is 2 minutes. We are also given that the length of the escalator is 150 meters.

Let's solve these equations to find the values of w and v.

Calculation

From the first equation, we have:

w + v = 150 / 3

From the second equation, we have:

w - v = 150 / 2

Adding these two equations, we get:

2w = (150 / 3) + (150 / 2)

Simplifying, we have:

2w = 50 + 75

2w = 125

w = 125 / 2

w = 62.5

Substituting the value of w in the first equation, we have:

62.5 + v = 150 / 3

Simplifying, we have:

62.5 + v = 50

v = 50 - 62.5

v = -12.5

Since the speed cannot be negative, we can conclude that there is an error in the given information or calculation.

Conclusion

Based on the given information, it seems there is an error in the calculation or the information provided. The calculated speed of the passenger walking is 62.5 m/min, but the speed of the escalator is calculated to be -12.5 m/min, which is not possible. It is recommended to double-check the given information or provide additional details to resolve the discrepancy.