Question

Решит задачу с распределительным свойством (если это возможно) На расстоянии 2 км 700 м от дачного посёлка находится пруд. Игорь от пруда, а Олег от посёлка выезжают на велосипедах од- новременно навстречу друг другу и встречаются через 6 мин. Най- ди скорость, с которой ехал каждый из них, если скорость Олега на 50 м/мин больше скорости Игоря.​

Answer 1

Ответ:2км 700м = 2 700м

1)  2 700 : 6 = 450 (м/мин) - скорость сближения

2)  (450  50); 2 = 200 (м/мин)  скорость Игоря

3)  200+ 50 = 250 (м/мин)-скорость

Олега Ответ; 200м/мин и 250м/мин.

Answer 2

Problem Analysis

The problem involves finding the speeds at which Igor and Oleg were traveling when they met, given that Oleg's speed was 50 m/min faster than Igor's speed.

Solution

Let's denote Igor's speed as x m/min. Then Oleg's speed can be represented as (x + 50) m/min.

The total distance covered by both Igor and Oleg when they met is the sum of the distances each traveled. Since they met after 6 minutes, we can calculate the distance each traveled using the formula: distance = speed × time.

Igor's distance = (x × 6) m Oleg's distance = ((x + 50) × 6) m

Since the total distance is 2700 m (2 km 700 m), we can set up the equation: (x × 6) + ((x + 50) × 6) = 2700

Solving for x will give us Igor's speed, and then we can find Oleg's speed by adding 50 to Igor's speed.

Calculation

Let's solve the equation: (x × 6) + ((x + 50) × 6) = 2700

Expanding and simplifying: 6x + 6x + 300 = 2700 12x + 300 = 2700 12x = 2400 x = 200

So, Igor's speed is 200 m/min and Oleg's speed is (200 + 50) = 250 m/min.

Therefore, Igor's speed was 200 m/min and Oleg's speed was 250 m/min.

I hope this helps! If you have any further questions, feel free to ask.