Question

На расстоянии 2 км 700 м от дачного поселка находится пруд. Игорь от пруда, а Олег от поселка выезжают на велосипедах одновременно навстречу друг другу и встречаются через 6 мин. Найди скорость , с которой ехал каждый из них, если скорость Олега на 50 м/мин больше скорости Игоря.

Answer 1

2км700м=2700м

2700:6=450м/мин- скорость сближения

450-50=400м/мин-была бы скорость сближения, если они ехали с одинак.скоростью

400:2=200м/мин- скоростьИгоря

200+50=250м/мин-скоростьОлега

Answer 2

Problem Analysis

We are given that there is a pond located 2 km 700 m away from a country house settlement. Igor starts from the pond, and Oleg starts from the settlement on their bicycles simultaneously, riding towards each other. They meet after 6 minutes. We need to find the speed at which each of them was riding, given that Oleg's speed is 50 m/min faster than Igor's.

Solution

Let's assume Igor's speed is x m/min. Since Oleg's speed is 50 m/min faster, his speed will be x + 50 m/min.

We can use the formula distance = speed × time to solve this problem.

The distance traveled by Igor in 6 minutes will be (x × 6) m, and the distance traveled by Oleg in 6 minutes will be ((x + 50) × 6) m.

According to the problem, the sum of the distances traveled by Igor and Oleg should be equal to the distance between the pond and the settlement, which is 2 km 700 m or 2700 m.

So, we can set up the equation:

(x × 6) + ((x + 50) × 6) = 2700

Simplifying the equation:

6x + 6(x + 50) = 2700

Solving for x:

12x + 300 = 2700

12x = 2400

x = 200

Therefore, Igor's speed is 200 m/min and Oleg's speed is 250 m/min.

Answer

Igor's speed is 200 m/min and Oleg's speed is 250 m/min.