Question

Два пловца спрыгнули одновременно с лодки и поплыли по реке в противоположных направлениях :Первый со средней скоростью 90м/мин , второй-40м/мин . Сколько метров проплывёт второй пловец, когда первый проплывет 270 м?

Answer 1

1.270м*90м/мин=3 мин

2.40м/мин*3мин =120м

Answer 2

Problem Analysis

We are given that two swimmers jump simultaneously from a boat and start swimming in opposite directions. The first swimmer swims at a speed of 90 m/min, while the second swimmer swims at a speed of 40 m/min. We need to determine how many meters the second swimmer will have swum when the first swimmer has swum 270 meters.

Solution

To solve this problem, we can use the formula: distance = speed × time.

Let's calculate the time it takes for the first swimmer to swim 270 meters: - Speed of the first swimmer = 90 m/min - Distance swum by the first swimmer = 270 meters - Time taken by the first swimmer = distance / speed = 270 / 90 = 3 minutes

Now, let's calculate the distance swum by the second swimmer in 3 minutes: - Speed of the second swimmer = 40 m/min - Time taken by the second swimmer = 3 minutes - Distance swum by the second swimmer = speed × time = 40 × 3 = 120 meters

Therefore, the second swimmer will have swum 120 meters when the first swimmer has swum 270 meters.

Answer

The second swimmer will have swum 120 meters when the first swimmer has swum 270 meters.