Question

В першій вазі було в 4 рази менше квітів, ніж у другій. Коли в першу вазу поставили ще 15 квітів, а в другу 3 квітки, то в обох вазах квітів стало порівну. Скільки квітів було в кожній вазі спочатку

Answer 1

                      Было          Стало

1-я ваза             х              х + 15

2-я ваза           4х             4х + 3

- - - - - - - - - - - - - - - - - - - - - - - - -

Уравнение:

4х + 3 = х + 15

4х - х = 15 - 3

3х = 12

х = 12 : 3

х = 4 (цветка) - было в первой вазе

4х = 4 · 4 = 16 (цветов) - было по второй вазе

Ответ: 4 цветка и 16 цветов.

Answer 2

Problem Analysis

We are given two vases, and initially, there were four times fewer flowers in the first vase than in the second vase. After adding 15 flowers to the first vase and 3 flowers to the second vase, the number of flowers became equal in both vases. We need to determine the initial number of flowers in each vase.

Solution

Let's assume the initial number of flowers in the first vase is x. According to the problem, the initial number of flowers in the second vase is four times greater than the first vase, so it would be 4x.

After adding 15 flowers to the first vase, the total number of flowers becomes x + 15. Similarly, after adding 3 flowers to the second vase, the total number of flowers becomes 4x + 3.

According to the problem, the total number of flowers in both vases became equal. So, we can set up the following equation:

x + 15 = 4x + 3

Now, let's solve this equation to find the value of x.

x + 15 = 4x + 3

15 - 3 = 4x - x

12 = 3x

x = 4

Therefore, the initial number of flowers in the first vase was 4, and the initial number of flowers in the second vase was 4 * 4 = 16.

Answer

The initial number of flowers in the first vase was 4, and the initial number of flowers in the second vase was 16.