
На одно и тоже число поделили числа 110 и 161 то получили соответственно остатки 2 и 26 найдите на
какое число поделили

Ответы на вопрос

110-2=108 161-26=135
оба числа делятся на 27



Solution:
To find the number by which both 110 and 161 were divided to get remainders of 2 and 26 respectively, we can use the following approach:
Let's assume the number we are looking for is denoted by x. Then we can express the given information in the form of congruences:
1. 110 ≡ 2 (mod x) 2. 161 ≡ 26 (mod x)
We can solve these congruences to find the value of x.
First, let's solve the congruence 110 ≡ 2 (mod x):
110 ≡ 2 (mod x)
This means that the difference between 110 and 2 is divisible by x. So, we have:
110 - 2 ≡ 0 (mod x) 108 ≡ 0 (mod x)
Next, let's solve the congruence 161 ≡ 26 (mod x):
161 ≡ 26 (mod x)
This means that the difference between 161 and 26 is divisible by x. So, we have:
161 - 26 ≡ 0 (mod x) 135 ≡ 0 (mod x)
Now, we need to find the common divisor of 108 and 135 to find the value of x.
Calculation:
The common divisors of 108 and 135 are 1, 3, 9, 27.
So, the number by which both 110 and 161 were divided to get remainders of 2 and 26 respectively is 27.
Therefore, x = 27.
This means that both 110 and 161 were divided by 27 to get the given remainders.


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