Question

Алгебра срочно нужна помощь !!!!!!!!! Дам много баллова) 2х-3(х-1)=4+2(х-1)б) х/3+х+1/4=2в) За 15 метров ткани двух сортов заплатили 28 р.40 к. 1 м ткани Ι сорта стоит 2 р., а 1 м ткани ΙΙ сорта - 1р.80 к. Сколько метров ткани каждого сорта было куплено ?

Answer 1

2х-3х+3=4+2х-2
-3х=-1
х=-1/3

х/3+х+1/4=2  приведем к общему знаменателю 12
4х+12х+3=24
16х=21
х=21/16=1 5/16

х ткань второго сорта
15-х ткань первого сорта
1,8х+2(15-х)=28,4
1,8х+30-2х=28,4
-0,2х=-1,6
х=8м ткань второго сорта
15-8=7м ткань первого сорта

Answer 2

a) 2x - 3(x-1) = 4 + 2(x-1)

First, distribute the -3: 2x - 3x + 3 = 4 + 2x - 2

Combine like terms: -x + 3 = 2x + 2

Subtract 2x from both sides: -3 = 3x + 2

Subtract 2 from both sides: -5 = 3x

Divide by 3: x = -5/3

b) x/3 + x + 1/4 = 2

First, find a common denominator for the fractions: Multiply the whole equation by 12 to clear the fractions: 4x + 12x + 3 = 24

Combine like terms: 16x + 3 = 24

Subtract 3 from both sides: 16x = 21

Divide by 16: x = 21/16

c) Let's call the number of meters of fabric of the first type x, and the number of meters of fabric of the second type y.

We have the following system of equations: x + y = 15 2x + 1.8y = 28.4

Multiply the first equation by 2: 2x + 2y = 30

Subtract the first equation from the second: 0.8y = 2.4

Divide by 0.8: y = 3

Substitute y back into the first equation: x + 3 = 15 x = 12

So, 12 meters of fabric of the first type and 3 meters of fabric of the second type were bought.