Question

Из одного города в другой выехал автобус со скоростью 56(целых)2/5 км/ч. Через 1 час вслед за ним выехала легковая машина. Через 2 часа она догнал автобус и отъехала от него на расстояние 10 км. Найдите скорость легковой машины.

Answer 1

Автобус в пути был 3 часа, и проехал он за это время 56ц2/5 х 3=168ц6/15 км. Легковая машина всего преодолела 168ц6/15 + 10км=178ц6/15к, т.к обогнала автобус на 10км. Но ехала легковушка на 1ч меньше, т.е. 2часа.
178ц6/15 делим на 2ч получаем 89ц1/5 или если перевести в десятичную дробь, то 89,2 км/ч.

Answer 2

Problem Analysis

We are given that a bus travels at a speed of 56 2/5 km/h, and after 1 hour, a car starts following the bus. After 2 hours, the car catches up to the bus and is 10 km ahead of it. We need to find the speed of the car.

Solution

Let's break down the problem step by step:

1. The bus travels at a speed of 56 2/5 km/h. After 1 hour, it has traveled 56 2/5 km. 2. After 2 hours, the car catches up to the bus and is 10 km ahead of it. 3. Let's assume the speed of the car is x km/h. 4. In 2 hours, the car travels a distance of 2x km. 5. Since the car catches up to the bus, the total distance traveled by the car is equal to the distance traveled by the bus plus the 10 km lead. 6. Therefore, we can set up the equation: 2x = 56 2/5 + 10.

Now, let's solve the equation to find the speed of the car:

2x = 56 2/5 + 10

To add the mixed number and the whole number, we need to convert the mixed number to an improper fraction:

2x = 56 2/5 + 10 = (56 * 5 + 2)/5 + 10 = (282/5) + 10 = (282 + 50)/5 = 332/5

To solve for x, we divide both sides of the equation by 2:

2x/2 = (332/5)/2 x = (332/5)/2 x = (332/5) * (1/2) x = 332/10 x = 33.2

Therefore, the speed of the car is 33.2 km/h.

Answer

The speed of the car is 33.2 km/h.