Question

Треугольник ABC вписан в окружность с центром O. Найдите угол BOC , если угол BAC равен 32°.

Answer 1

Угол BOC измеряется половиной дуги на которую он опирается. Центральный угол этой дуги в 2 раза больше. угол ВAC = 32*2 = 64 градуса

Answer 2

I can help you with your math problem. Here is the solution:

The angle BOC is the central angle of the circle, and the angle BAC is the inscribed angle of the same arc BC. Therefore, the angle BOC is twice the angle BAC, according to the inscribed angle theorem. So, if the angle BAC is 32°, then the angle BOC is 2 * 32° = 64°.

You can see a detailed explanation and a diagram of this problem on [this website](https://yandex.ru/tutor/subject/problem/?problem_id=T1310). You can also watch a video tutorial on [this YouTube channel](https://www.youtube.com/watch?v=g_9cYxHcy2c).

I hope this helps you. Do you have any other questions?