Question

Толя купил 4 книги. Все книги без первой стоят 48 к, без второй 46 к, без третьей 42 к, без четвертой 38 к. Сколько стоит каждая книга? пожалуйста с объяснениями.

Answer 1

2-я+3-я+4-я=48
1-я+3-я+4-я=46
1-я+2-я+4-я=42
1-я+2-я+3-я=38. Сложим все и получим: 3 1-х +3 2-х + 3 3-х +3 4-х = 174
1+2+3+4 = 174:3 = 58 коп.

Answer 2

Problem Analysis

Tolya bought 4 books, and the prices of the books without the first, second, third, and fourth books are given as 48k, 46k, 42k, and 38k respectively. We need to find the price of each book.

Solution

Let's assume the price of the first book is x.

According to the given information: - The price of the second book is 48k - x. - The price of the third book is 46k - (48k - x) = x - 2k. - The price of the fourth book is 42k - (x - 2k) = 44k - x.

To find the value of x, we can set up an equation using the information above: x + (48k - x) + (x - 2k) + (44k - x) = 38k.

Simplifying the equation: 48k - x + x - 2k + 44k - x = 38k, 90k - 2x = 38k, 90k - 38k = 2x, 52k = 2x, x = 26k.

Therefore, the price of the first book is 26k.

Using this information, we can find the prices of the other books: - The price of the second book is 48k - 26k = 22k. - The price of the third book is 26k - 2k = 24k. - The price of the fourth book is 44k - 26k = 18k.

So, the prices of the four books are: - First book: 26k - Second book: 22k - Third book: 24k - Fourth book: 18k.

Please note that the values of k and the currency used are not specified in the question, so we cannot provide the exact prices in a specific currency.