Question

Веревку разрезали на две части так, что первая часть была в 5 раз больше второй. Какова длина каждой части веревки, если первая часть на 20м больше второй? Какова длина веревки?

Answer 1

x- первая часть веревки

у - вторая часть веревки

$\left \{ {{x=5y} \atop {x=y+20}} \right.$

5y=y+20

4y=20

y=5(м)

x=5*5=25 (м)

Answer 2

Пусть вторая часть рана х.Тогда первая равна 5х(так как больше в 5 раз).Первая также равна х а вторая х-20(так как вторая на 20 меньше первой).Приравниваем обе части,составляем уравнение х+5х=х+(х-20)

4х=20

Х=5

Х2=25

Answer 3

Problem Analysis

We are given that a rope was cut into two parts, with the first part being 5 times larger than the second part. We are also given that the first part is 20 meters longer than the second part. We need to find the length of each part and the total length of the rope.

Solution

Let's assume the length of the second part of the rope is x meters. According to the given information, the first part of the rope is 5 times larger than the second part, so its length is 5x meters. We are also told that the first part is 20 meters longer than the second part, so we can set up the following equation:

5x = x + 20

Simplifying the equation, we have:

4x = 20

Dividing both sides of the equation by 4, we get:

x = 5

Therefore, the length of the second part of the rope is 5 meters. Since the first part is 5 times larger, its length is:

5x = 5 * 5 = 25

So, the length of the first part of the rope is 25 meters.

To find the total length of the rope, we add the lengths of the two parts:

Total length = Length of first part + Length of second part = 25 + 5 = 30 meters

Therefore, the length of each part of the rope is 25 meters and 5 meters, and the total length of the rope is 30 meters.

Answer

The length of the first part of the rope is 25 meters, the length of the second part is 5 meters, and the total length of the rope is 30 meters.