Question

Мастер выполняет заказ за 9 часов. ученику потребуется на выполнение этого же заказа времени в 8 раз больше.сколько часов потратит мастер вместе с учеником на выполнение заказа при совместной работе?помогите пж

Answer 1

9×8=72
1/9+1/72=9/72=1/8 за 8 часов закочить

Answer 2

Мастер=х деталей\в час 
Время мастера=9 ч
Работа мастера=9х
Время ученика=1\8х деталей в час
Время уч=9*8=72 ч
Работа уч=9х
Ответ:
9х:(х+1\8х)=5 ч

Answer 3

Calculation of Time Required for Master and Apprentice to Complete the Order

To calculate the total time required for the master and apprentice to complete the order, we need to consider that the master completes the order in 9 hours, and the apprentice takes 8 times longer to complete the same order.

Let's denote the time taken by the apprentice as x hours. According to the given information, we can set up the following equation:

9 + x = 8x

Simplifying the equation, we get:

9 = 7x

Dividing both sides of the equation by 7, we find:

x = 9/7

Therefore, the apprentice will take 9/7 hours to complete the order.

To find the total time required for the master and apprentice to complete the order together, we add their individual times:

Total time = 9 hours (master) + 9/7 hours (apprentice)

Simplifying the expression, we can convert the mixed fraction to an improper fraction:

Total time = 63/7 hours + 9/7 hours

Combining the fractions, we get:

Total time = (63 + 9)/7 hours

Simplifying further, we find:

Total time = 72/7 hours

Therefore, the master and apprentice will take 72/7 hours to complete the order together.

Please note that the above calculations are based on the given information and assumptions.