Question

4 3/5 : (1 2/3-3 1/5)+1 3/8 Помогите решить

Answer 1

23/5 : (5/3 - 16/5) + 11/8 = 23/5 : ( -11/5 ) + 11/8 = - 23*5/11*5 + 11/8 = 11/8 - 23/11 = (121-184)/88= - 63/88

Answer 2

I can help you with math problems. Here is how to solve this one:

First, convert all the mixed fractions to improper fractions:

$$4 \frac{3}{5} = \frac{4 \times 5 + 3}{5} = \frac{23}{5}$$

$$1 \frac{2}{3} = \frac{1 \times 3 + 2}{3} = \frac{5}{3}$$

$$3 \frac{1}{5} = \frac{3 \times 5 + 1}{5} = \frac{16}{5}$$

$$1 \frac{3}{8} = \frac{1 \times 8 + 3}{8} = \frac{11}{8}$$

Then, perform the subtraction and addition in the parentheses:

$$\left(1 \frac{2}{3} - 3 \frac{1}{5}\right) + 1 \frac{3}{8} = \left(\frac{5}{3} - \frac{16}{5}\right) + \frac{11}{8}$$

To subtract or add fractions, we need to find a common denominator. The least common multiple of 3, 5, and 8 is 120. So we multiply each fraction by a factor that makes the denominator 120:

$$\left(\frac{5}{3} \times \frac{40}{40} - \frac{16}{5} \times \frac{24}{24}\right) + \frac{11}{8} \times \frac{15}{15} = \left(\frac{200}{120} - \frac{384}{120}\right) + \frac{165}{120}$$

Now we can subtract and add the fractions with the same denominator:

$$\left(\frac{200}{120} - \frac{384}{120}\right) + \frac{165}{120} = \frac{-184}{120} + \frac{165}{120} = \frac{-19}{120}$$

Finally, we divide the fraction by the greatest common factor of the numerator and denominator to simplify it:

$$\frac{-19}{120} \div \frac{1}{-1} = \frac{19}{120}$$

So the final answer is:

$$4 \frac{3}{5} : \left(1 \frac{2}{3} - 3 \frac{1}{5}\right) + 1 \frac{3}{8} = \frac{19}{120}$$

I hope this helps you understand how to solve this problem. If you have any other questions, feel free to ask me.Ответь+подробно.+4+3/5+:+(1+2/3-3+1/5)+1+3/8+Помогите+решить