Question

ПОМОГИТЕ ПОЖАЛУЙСТА СРОЧНО! Мотоциклист догоняет велосипедиста. Сейчас между ними 23,4 км. Скорость велосипедиста 13,5 км/ч. Найдите скорость мотоциклиста, если известно, что мотоциклист догонит велосипедиста через 2/3 часа .

Answer 1

Ответ:

48,6 км/ч

Пошаговое объяснение:

пусть х скорость мотоциклиста, тогда х *2/3 проедет путь мотоциклист, 13,5*2/3=9 км проедет велосипедист за 2/3 часа. весь путь мотоциклиста 23,4+9=32,4 . х*2/3=32,4, х=48,6 км/ч

Answer 2

Calculation of the Motorcyclist's Speed

To find the speed of the motorcyclist, we can use the formula:

Speed = Distance / Time

Given that the distance between the motorcyclist and the cyclist is 23.4 km, and the cyclist's speed is 13.5 km/h, we need to calculate the time it takes for the motorcyclist to catch up to the cyclist.

The time can be calculated using the formula:

Time = Distance / Speed

In this case, the distance is 23.4 km, and the speed of the cyclist is 13.5 km/h. Let's calculate the time it takes for the motorcyclist to catch up to the cyclist:

Time = 23.4 km / 13.5 km/h

Calculating this, we find that the time is approximately 1.733 hours.

Now, we know that the motorcyclist will catch up to the cyclist in 2/3 hours. To find the motorcyclist's speed, we can divide the distance between them by the time it takes for the motorcyclist to catch up to the cyclist.

Motorcyclist's Speed = Distance / Time

Motorcyclist's Speed = 23.4 km / (2/3) hours

To simplify the calculation, we can convert 2/3 hours to minutes. Since there are 60 minutes in an hour, 2/3 hours is equal to (2/3) * 60 = 40 minutes.

Motorcyclist's Speed = 23.4 km / (40/60) minutes

Simplifying further, we have:

Motorcyclist's Speed = 23.4 km / (2/3) km/minute

Dividing the distance by the time, we find:

Motorcyclist's Speed = 23.4 km * (3/2) km/minute

Calculating this, we find that the motorcyclist's speed is approximately 35.1 km/h.

Please note that the above calculation assumes a constant speed for both the motorcyclist and the cyclist throughout the entire duration of the chase.