Question

Известно что график функции у=кх+l проходит через точки (2;3) и (3;2). Найдите k и l. Гадо решить систему учитель сказал подставить вместо х и у точки

Answer 1

Для первой решаем так,
3=2k+l
-2k=l-3
k=-1/2l+3/2


Для второй, 2=3k+l
Аналогично

Answer 2

#### Finding the values of k and l in the equation y = kx + l To find the values of k and l in the equation y = kx + l, we can use the given points (2, 3) and (3, 2) that the graph of the function passes through. Let's substitute the x and y values of each point into the equation and solve the resulting system of equations. Substituting (2, 3): 3 = 2k + l -- (1) Substituting (3, 2): 2 = 3k + l -- (2) To solve this system of equations, we can use various methods such as substitution or elimination. Let's use the elimination method. Subtracting equation (1) from equation (2), we get: 2 - 3 = 3k + l - (2k + l) -1 = k Now that we have the value of k, we can substitute it back into either equation (1) or (2) to find the value of l. Using equation (1): 3 = 2(-1) + l 3 = -2 + l l = 3 + 2 l = 5 Therefore, the values of k and l in the equation y = kx + l are: k = -1 l = 5 **Note:** The solution to the system of equations is k = -1 and l = 5.