Question

Решите уравнения: А)(13/28-х)+17/28=23/28 Б)43/47-(х-21/47)=25/47 Решите прошууууу!!!!!!!!

Answer 1

А)13/28-х=23/28-17/28
13/28-х=6/28
х=13/28-6/28
х=7/28=1/4
б)х-21/47=43/47-25/47
х-21/47=18/47
х=18/47+21/47
х=39/47

Answer 2

Solution to equation A:

To solve the equation (13/28 - x) + 17/28 = 23/28, we can follow these steps:

Step 1: Combine like terms on the left side of the equation: (13/28 - x) + 17/28 = 23/28 (13/28 + 17/28) - x = 23/28 30/28 - x = 23/28

Step 2: Simplify the left side of the equation: 30/28 - x = 23/28 (30 - 28x)/28 = 23/28

Step 3: Cross-multiply: 28(30 - 28x) = 23(28) 840 - 784x = 644

Step 4: Solve for x: -784x = 644 - 840 -784x = -196 x = -196 / -784 x = 1/4

Therefore, the solution to equation A is x = 1/4.

Solution to equation B:

To solve the equation 43/47 - (x - 21/47) = 25/47, we can follow these steps:

Step 1: Simplify the equation by removing the parentheses: 43/47 - x + 21/47 = 25/47

Step 2: Combine like terms on the left side of the equation: (43 + 21)/47 - x = 25/47 64/47 - x = 25/47

Step 3: Simplify the left side of the equation: 64/47 - x = 25/47

Step 4: Subtract 64/47 from both sides of the equation: - x = 25/47 - 64/47 - x = -39/47

Therefore, the solution to equation B is x = -39/47.

I hope this helps! Let me know if you have any further questions.