Question

В 11ч с аэропорта вылетели одновременно с про чего положенных направлениях два самолета в 14 часов часов расстояние между ними было 2500 40 км один из них летел со скоростью 600 20 километров в час с какой скоростью летел другой самолет помогите решить

Answer 1

14-11=3 часа-время в пути.2)620*3=1860 км-пролетел первый за 3 часа.3)3540-1860=1680 км-пролетел второй за 3 часа.4)1680:3=560 км/ч-скорость второго самолёта.

Answer 2

Problem Analysis

We have two planes that took off simultaneously from an airport at 11:00. At 14:00, the distance between them was 2500 km. One of the planes was flying at a speed of 600 km/h. We need to determine the speed of the other plane.

Solution

Let's assume that the speed of the second plane is x km/h.

To solve this problem, we can use the formula: distance = speed × time.

For the first plane: - Speed = 600 km/h - Time = 14:00 - 11:00 = 3 hours - Distance = Speed × Time = 600 km/h × 3 hours = 1800 km

For the second plane: - Speed = x km/h - Time = 3 hours - Distance = 2500 km - 1800 km = 700 km

Now we can set up an equation to solve for x: 700 km = x km/h × 3 hours

To find x, we can divide both sides of the equation by 3: 700 km / 3 hours = x km/h

Calculation

Let's calculate the speed of the second plane:

700 km / 3 hours = x km/h

x ≈ 233.33 km/h

Answer

The second plane was flying at a speed of approximately 233.33 km/h.

Please let me know if you need any further assistance!