Question

Помогите решить задачу( В обрабатывающем цехе механического завода имеются два станка с программным управлением. Первый станок обрабатывает заготовки в два раза медленее,чем второй. Сколько заготовок обработал первый станок за час,если в цех поступили 12 заготовок и челез 2 часа работы станков обработка была закончена?

Answer 1

(x+2x)*2=12   Где x- скорость обработки первого, 2x- второго, 2 - время
2x+4x=12
6x=12
x=2з/ч

Answer 2

Problem Analysis

The problem involves two machines with programmable control in a mechanical workshop. The first machine processes workpieces at half the speed of the second machine. We need to determine how many workpieces the first machine processed in one hour, given that 12 workpieces were received in the workshop and both machines worked for 2 hours to complete the processing.

Solution

Let's denote the number of workpieces processed by the first machine as x and the number of workpieces processed by the second machine as y. We are given that the first machine processes workpieces at half the speed of the second machine, and both machines worked for 2 hours to complete the processing.

We can set up the following equations based on the given information: 1. x + y = 12 (Total workpieces processed is 12) 2. 0.5x * 2 + y * 2 = 12 (Work done by the first machine in 2 hours plus work done by the second machine in 2 hours is 12)

Calculation

Let's solve the system of equations to find the value of x.

From equation 1, we can express y in terms of x: y = 12 - x

Substitute the value of y in equation 2: 0.5x * 2 + (12 - x) * 2 = 12 x + 24 - 2x = 12 24 - x = 12 x = 24 - 12 x = 12

Answer

Therefore, the first machine processed 12 workpieces in one hour.

Additional Note

It's important to ensure that the units are consistent throughout the calculations. In this case, we've assumed that the time taken for processing is in hours, which aligns with the given information about the machines working for 2 hours.