Question

По плану 2 цеха должны выпустить 230 ст машин. Причём 2/9 плана 1-ого цеха состовляют столько же машин, сколько 80% плана 2-ого цеха. Каков план каждого цеха? Решать через уравнение!!!

Answer 1

Пусть план 1 цеха х машин, тогда план 2 цеха 230-х машин. 80%=8/10.

Составим и решим уравнение по условию задачи:

2/9*х=8/10*(230-х)

20х-16560+72х=0

92х=16560

х=180

Ответ: 180 машин план 1 цеха; 230-180=50 машин план второго цеха.

Answer 2

Problem Analysis

We are given that there are two workshops, and the combined plan is to produce 230 machines. Additionally, we are given that the first workshop's plan is 2/9 of the total plan, and the number of machines produced by the first workshop is the same as 80% of the second workshop's plan. We need to find the plan for each workshop.

Solution

Let's assume the plan for the first workshop is x and the plan for the second workshop is y.

From the given information, we can form the following equations:

1. The combined plan is to produce 230 machines: - x + y = 230

2. The first workshop's plan is 2/9 of the total plan: - x = (2/9) * (x + y)

3. The number of machines produced by the first workshop is the same as 80% of the second workshop's plan: - x = 0.8 * y

We can solve this system of equations to find the values of x and y.

Solving the Equations

Let's solve the system of equations using substitution or elimination method.

From equation 3, we have: x = 0.8 * y

Substituting this value of x in equation 2, we get: 0.8 * y = (2/9) * (x + y)

Simplifying the equation: 0.8 * y = (2/9) * (0.8 * y + y)

Multiplying both sides by 9 to eliminate the fraction: 7.2 * y = 2.4 * y + 2.4 * y

Simplifying further: 7.2 * y = 4.8 * y

Subtracting 4.8 * y from both sides: 7.2 * y - 4.8 * y = 0

Simplifying: 2.4 * y = 0

Since 2.4 * y = 0, we can conclude that y = 0.

Substituting this value of y in equation 3, we get: x = 0.8 * 0

Therefore, x = 0.

Conclusion

The plan for each workshop is 0. This means that according to the given information, neither workshop has a plan to produce any machines.

Please note that the solution obtained is based on the given information and the equations formed. If there is any additional information or if the equations are incorrect, the solution may change.