Question

Відстань від пункту А до пункту В дорівнює 112 км. Одночасно з цих пунктів назустріч один одному виїхали два велосипедисти і зустрілися через 3,5 год. Знайди швидкість першого велосипедиста, якщо швидкість другого на 4 км/год більша, ніж швидкість першого. (У відповідь записуєте число) 

Answer 1

Ответ:

14

Пошаговое объяснение:

x - скорость 1-го велосипедиста, км/ч.

3,5(x+x+4)=112    |×2/7

2x+4=32              |2

x=16-2=14 км/ч - скорость 1-го велосипедиста.

Answer 2

Problem Analysis

We are given that the distance between point A and point B is 112 km. Two cyclists start simultaneously from these points and meet each other after 3.5 hours. The speed of the second cyclist is 4 km/h greater than the speed of the first cyclist. We need to find the speed of the first cyclist.

Solution

Let's assume the speed of the first cyclist is x km/h. Since the speed of the second cyclist is 4 km/h greater, the speed of the second cyclist is x + 4 km/h.

We can use the formula distance = speed × time to solve this problem. The distance traveled by the first cyclist is equal to the distance traveled by the second cyclist, which is 112 km.

For the first cyclist: distance = speed × time 112 = x × 3.5 (Equation 1)

For the second cyclist: distance = speed × time 112 = (x + 4) × 3.5 (Equation 2)

We can solve this system of equations to find the value of x.

Solving the Equations

Let's solve the system of equations (Equation 1 and Equation 2) to find the value of x.

From Equation 1: 112 = x × 3.5

Dividing both sides of the equation by 3.5: 32 = x

From Equation 2: 112 = (x + 4) × 3.5

Expanding the equation: 112 = 3.5x + 14

Subtracting 14 from both sides of the equation: 98 = 3.5x

Dividing both sides of the equation by 3.5: 28 = x

Therefore, the speed of the first cyclist is 28 km/h.

Answer

The speed of the first cyclist is 28 km/h.