Question

Туристы за 3 дня проехали 460км.Путь их в первый день относится к пути во второй день как 7:5.Отношение пути туристов во второй день к пути в третий день равно 3:2.Сколько километров они проехали в первый второй и третий день?

Answer 1

Пусть в первый день прошли 7х км, то во второй день 5х км.В третий день=10х/3Составим уравнени7х+5х+10х/3=46046х/3=460х=3*460/46=30Плдучаем в первый день прошли 30*7=210 кмво второй=5*30=150 кмв третий день=30*10/3=100 км

Answer 2

Problem Analysis

We are given that a group of tourists traveled a total distance of 460 km over the course of 3 days. The ratio of the distance traveled on the first day to the distance traveled on the second day is 7:5. The ratio of the distance traveled on the second day to the distance traveled on the third day is 3:2. We need to find the distances traveled on each of the three days.

Solution

Let's assume that the distance traveled on the first day is 7x km and the distance traveled on the second day is 5x km. According to the given ratio, the distance traveled on the third day would be (5x * 3) / 2 km.

We can set up the following equation to represent the total distance traveled:

7x + 5x + (5x * 3) / 2 = 460

Simplifying the equation:

14x + 10x + 15x = 920

39x = 920

Solving for x:

x = 920 / 39

x ≈ 23.59

Now we can calculate the distances traveled on each day:

- First day: 7x ≈ 7 * 23.59 ≈ 165.13 km - Second day: 5x ≈ 5 * 23.59 ≈ 117.95 km - Third day: (5x * 3) / 2 ≈ (5 * 23.59 * 3) / 2 ≈ 176.93 km

Therefore, the tourists traveled approximately 165.13 km on the first day, 117.95 km on the second day, and 176.93 km on the third day.

Answer

The tourists traveled approximately 165.13 km on the first day, 117.95 km on the second day, and 176.93 km on the third day.