Question

1)13x+10=6x-4 2)-5(x+2)=-(-2+x)

Answer 1

1) 13x+10=6x-4

13х-6х=-4-10

7х=-14

х=-2

2) -5(x+2)=-(-2+x)

-5х-10=2-х

-5х+х=2+10

-4х=12

х=-3

Answer 2

13х+10=6х-4

13х-6х+10=-4

7х+10=-4

7х=-4-10

7х=-14

х=-14÷7

х=-2

-5×(х+2)=-(+2+х)

-5х+-10=-(+2+х)

-5х-10=-2+х

-10=-2+х+5х

-10=-2+6х

-10+2=6х

-8=6х

х=6×-8

х=-48

Answer 3

Sure, let's solve these equations step by step.

Equation 1: $13x + 10 = 6x - 4$

First, let's get all the $x$ terms on one side and the constant terms on the other side:

$13x - 6x = -4 - 10$ $7x = -14$

Now, divide both sides by 7 to solve for $x$:

$x = -2$

Equation 2: $-5(x + 2) = -(-2 + x)$

First, distribute the $-5$ on the left side:

$-5x - 10 = 2 - x$

Next, get all the $x$ terms on one side and the constant terms on the other side:

$-5x + x = 2 + 10$ $-4x = 12$

Divide both sides by $-4$ to solve for $x$:

$x = -3$

So, the solutions for the given equations are $x = -2$ for the first equation and $x = -3$ for the second equation.