Question

из города в противоположных направлениях одновременно выехали два велосипедиста. Через 3 ч.расстояние между ними было 78 км. Чему равна скорость второго велосипедиста, если известно, что первый велосипедист проехал за 1 ч на 2 км больше второго?

Answer 1

1)2*3=6(км)-второй больше
2)78-6=72(км)-оба без разницы в скорости
3)72:2=36(км)-второй
4)36+2=38(км)-первый

Answer 2

2•3=6
78-6=72
72:2=36
36+2=38
ответ:38

Answer 3

Problem Analysis

We have two cyclists who start simultaneously in opposite directions. After 3 hours, the distance between them is 78 km. We also know that the first cyclist traveled 2 km more than the second cyclist in 1 hour. We need to find the speed of the second cyclist.

Solution

Let's assume the speed of the first cyclist is v1 km/h and the speed of the second cyclist is v2 km/h.

We know that the distance traveled by the first cyclist in 1 hour is v1 km, and the distance traveled by the second cyclist in 1 hour is v2 km.

According to the given information, the first cyclist traveled 2 km more than the second cyclist in 1 hour. Therefore, we can write the equation:

v1 = v2 + 2

After 3 hours, the distance between the two cyclists is 78 km. We can write the equation:

3(v1 + v2) = 78

Now we can solve these two equations to find the value of v2, the speed of the second cyclist.

Calculation

Let's substitute the value of v1 from the first equation into the second equation:

3((v2 + 2) + v2) = 78

Simplifying the equation:

3(2v2 + 2) = 78

6v2 + 6 = 78

6v2 = 72

v2 = 12

Answer

The speed of the second cyclist is 12 km/h.