Question

У Коли и Максима 11 мячей. У Коли на 3 мяча больше, чем у Максима. Сколько мячей у мальчиков.

Answer 1

(11-3):2=8:2=4 мяча у Максима                                                                          4+3=7 мячей у Коли                                                                                         (7+4=11 мячей на двоих)

Answer 2

1) 11- 3 = 8(мячей) было бы у мальчиков, если у каждого поровну мячей
2) 8 : 2 = 4(мяча) у Максима
3) 4 + 3 = 7(мячей) у Коли
Ответ: 7мячей у Коли; 4 мяча - у Максима.

Answer 3

Problem Statement

The problem states that Kolya and Maxim have a total of 11 balls, with Kolya having 3 more balls than Maxim. The task is to determine the number of balls each boy has.

Solution

Let's solve this step by step.

1. Let's assume the number of balls Kolya has as x. 2. According to the given information, Maxim has 3 fewer balls than Kolya, so the number of balls Maxim has is x - 3. 3. The total number of balls they have together is 11, so we can create the equation: x + (x - 3) = 11.

Now, let's solve for x to find the number of balls Kolya has.

Calculation

``` x + (x - 3) = 11 2x - 3 = 11 2x = 11 + 3 2x = 14 x = 14 / 2 x = 7 ```

Answer

So, Kolya has 7 balls, and Maxim has 7 - 3 = 4 balls.