Question

2 6\7 · 3 5\6+ 3 6\7· 3 1\6=

Answer 1

2 6\7×3 5\6+3\7×31\6= 87

Answer 2

To solve this expression, you can follow the order of operations (PEMDAS/BODMAS):

1. First, multiply the fractions:

   • 2 \frac{6}{7} \cdot 3 \frac{5}{6} = \left(2 + \frac{6}{7}\right) \cdot \left(3 + \frac{5}{6}

2. Now, add the whole numbers and fractions separately:

   • $2 + \frac{6}{7} = \frac{14}{7} + \frac{6}{7} = \frac{20}{7}$
   • $3 + \frac{5}{6} = \frac{18}{6} + \frac{5}{6} = \frac{23}{6}$

3. Multiply the results:

   • $\frac{20}{7} \cdot \frac{23}{6} = \frac{20 \cdot 23}{7 \cdot 6}$

Now, you can simplify the fraction by finding the greatest common divisor (GCD) of the numerator and denominator and dividing both by it:

GCD(20, 7) = 1 (There are no common factors other than 1) GCD(23, 6) = 1

So, the fraction is already in simplest form, and the result of the expression is:

$\frac{20 \cdot 23}{7 \cdot 6} = \frac{460}{42} = \frac{230}{21}$

Therefore, $2 \frac{6}{7} \cdot 3 \frac{5}{6} + 3 \frac{6}{7} \cdot 3 \frac{1}{6} = \frac{230}{21}$.