Question

Принадлежит ли графику y=x²-2x+3,точка A(2;3),B(-1;5)?

Answer 1

Нет не принадлежит это точно

Answer 2

Checking the Points on the Graph

To determine if the points A(2, 3) and B(-1, 5) belong to the graph of y=x²-2x+3, we can substitute the x and y values of the points into the equation and check if the equation holds true for both points.

For point A(2, 3): - Substituting x=2 and y=3 into the equation y=x²-2x+3 gives: 3 = 2² - 2*2 + 3 3 = 4 - 4 + 3 3 = 3

For point B(-1, 5): - Substituting x=-1 and y=5 into the equation y=x²-2x+3 gives: 5 = (-1)² - 2*(-1) + 3 5 = 1 + 2 + 3 5 = 6

As the equation doesn't hold true for point B(-1, 5), it means that point B does not belong to the graph of y=x²-2x+3. However, the equation holds true for point A(2, 3), so point A belongs to the graph of y=x²-2x+3.

Conclusion: - Point A(2, 3) belongs to the graph of y=x²-2x+3. - Point B(-1, 5) does not belong to the graph of y=x²-2x+3.

Additional Information

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