Question

1) f(x) = x2-3x - 3;​

Answer 1

Ответ:

f'(x)= 2x-3

2x-3=0

x=1,5

якщо це знайти похідну то так яка умова була.

Answer 2

It looks like you've provided a quadratic function:

$f(x) = x^2 - 3x - 3$

This is a polynomial function of degree 2. If you have a specific question or task related to this function, feel free to let me know!