Question

1/12 - х= 2 5/12; 3+x= 5/9

Answer 1

Ответ:

х= -7/3

х= -22/9

Пошаговое объяснение:

Answer 2

1)-x=2 5/12-1/12

-x=7/3

x=-7/3

2)3+x=5/9

x=5/9-3

x= -22/9

Answer 3

To solve the equations:

1. $\frac{1}{12} - x = \frac{2}{12}$

First, let's make the fractions have a common denominator, which is 12 in this case:

$\frac{1}{12} - x = \frac{2}{12}$

Now, subtract $\frac{2}{12}$ from both sides of the equation:

$\frac{1}{12} - \frac{2}{12} - x = 0$

$\frac{-1}{12} - x = 0$

Next, add $\frac{1}{12}$ to both sides to isolate $x$:

$-x = \frac{1}{12}$

Now, multiply both sides by -1 to solve for $x$:

$x = -\frac{1}{12}$

So, $x = -\frac{1}{12}$.

2. $3 + x = \frac{5}{9}$

Subtract 3 from both sides to isolate $x$:

$x = \frac{5}{9} - 3$

To subtract fractions, they need a common denominator. The common denominator here is 9:

$x = \frac{5}{9} - \frac{3 \cdot 9}{9}$

$x = \frac{5}{9} - \frac{27}{9}$

Now that the fractions have the same denominator, subtract the numerators:

$x = \frac{5 - 27}{9}$

$x = \frac{-22}{9}$

So, $x = -\frac{22}{9}$.