Question

Log0.2(x+4) < log0.2^2

Answer 1

Ответ:

x∈(-4;-2)

Пошаговое объяснение:

$log0.2(x+4) < log0.2(2)\\x+4$

x>-4

Answer 2

Let's solve this logarithmic inequality together. To make things simpler, let's express both sides of the inequality with the same base:

$\log_{0.2}(x + 4) < \log_{0.2}^2$

Now, we can drop the logarithmic notation and focus on the inequality:

$x + 4 < (\log_{0.2}^2)$

Solving for $x$:

$x < (\log_{0.2}^2) - 4$

Now, if you know the numerical value of $\log_{0.2}^2$, you can evaluate it and subtract 4 to find the range of $x$ that satisfies the inequality. Keep in mind that the base of the logarithm is 0.2, which is less than 1, so the inequality might have some specific constraints based on the properties of logarithmic functions.